Waec 2017 Chemistry (Practical Alternative A Answers – May/June Expo
»Exam Time: Chemistry 3 (Practical Alternative A) 09.30am – 11.30am
NOTE THAT ^ MEANS Raise to power. Draw Your Table As Usual And Input The Following:- Volume of pipette=25.00cm^3 indicator used- Methyl orange colour change at end point-yellow to orange/purple Note Use Your School End Point. ==============
1) Tabulate Burette reading|Final burette reading(cm^3)|Initial burette reading (cm^3)| Volume of acid used(cm^3)| Rough- 24.10,0.00,24.10 First- 23.80, 0.00, 23.80 Second- 23.75, 0.00, 23.70 Third- 23.75, 0.00, 23.75 Average volume of A used = 23.80 + 23.70 + 23.75cm^3/3 =23.75cm^3
1bi) CAVA/CcVc=2/1 Cc=CAVA/2VC =0.100*23.75Moldm^-3/2*25.00 =0.0475moldm^-3 amount of A used = 0.100x VA/1000=0.100*23.75/1000 =0.00237 2moles Of A = 1mole of C 0.002375mol of A = 0.002375mol/2 100cm^3 of C contain 0.00237*100mol/2*25 =0
1000cm3ofCcontained0.002375x1000mol 2x25 =0.0475mol concentration of C in moldm-3 =0.0475moldm-3
1bii) Molar mass of Bing mol-1: Molar mass of Na2CO3.yH2O=mass concentration of Bingdm-3 molar concentration of Binmoldm-3 =13.6gdm-3 0.0475moldm-3 =286gmol-1
1biii) Molar mass of Na2CO3 =[(2×23)+12+(16×3)]=106gmol-1 Mass of anhydrous Na2CO3=106x0.0475gdm-3 =5.035gdm-3 Mass of water=13.6-5.035gdm-3 =8.565gdm-3 Mass of Na2CO3 =Molar mass of Na2CO3 Mass of water y×Molar mass of water 5.035=106 8.565 18y y =106x8.565 5.035x18 =10
2) Tabulate Test (a)(i)Fn+H2O,then filter
Observation White residue and blue filtrate was observed
Inference Fn is a mixture of soluble and insoluble salts
Test (ii)Filtrate+NaOH(aq)in drops,then in excess
Observation A blue gelatinous precipitate which is insoluble in excess NaOH(aq)was formed
Inference Cu2+present
Test (iii)Filtrate+NH3(aq)in drops,then in excess
Observation A pale blue gelatinous precipitate was formed. The precipitate dissolves or is soluble in excess NH3(aq)to give a deep blue solution
Inference Cu2+confirmed
Test (iv)Filtrate+dil.HNO3 +AgNO3(aq)
Observation No visible reaction White precipitate formed
Inference Cl-present
Test +NH3(aq)in excess
Observation Precipitate dissolved in excess NH3(aq)
Inference Cl-confirmed ===============
2bi)First portion of residue +NaOH(aq) in drops, then in excess
Observation White powdery precipitate which is insoluble in excess NaOH(aq)
Inference Ca2+ present
Test 2bii)Second portion of residue + dil.HCl
Observation Effervescence/bubbles; colourless, odourless gas evolved. Gas turns lime water milky and turns damp blue litmus paper red.
Inference Gas is CO2 CO3^2- or HCO3- present ===============
3i) lime juice is acidic in nature and the colour of methyl orange in acidic medium is red
3ii) Iron(iii)chloride will be reduced to iro(ii) with yellow deposit of sulphur
3iii) The color of KM2O4 is decolorized because SO2(g) acts as a reducing agent.
3iv) Addition of ethanoic acid to KCO3 results to the liberation of a colorless and odorless gas CO2 which turns lime water milky ===============
=====KEEP REFRESHING=====
Tell Your Friends About [maxiexam] ENSURE YOU SUBSCRIBE FOR THE NEXT[] EnJOY =========================
Post a Comment